Question

Two marbles are drawn without replacement from a box with 3 White, 2 green, 2 red, and 1 Blue Marble.
Find the probability. Both marbles are white

Answer 1

Answer:

$\frac{3}{28}$

Step-by-step explanation:

Te meaning of without replacement is once the ball is picked from the stock it cannot be put back

Hre there are total 8 balls and 3 white balls

probability of picking 1st white is $\frac{3}{8}$

now only 2 white and total is 7( one ball has already been picked)

therefore probability of picking 2nd white ball is $\frac{2}{7}$

both the action are independent events

therefore, probability of picking 2 white balls is  $\frac{3}{8}$ × $\frac{2}{7}$

= $\frac{3}{28}$

Answer 2

Answer:$\frac{3}{28}$

Step-by-step explanation:

Given a box contains 3 White ,2 green,2 red & 1 Blue marble

We have to draw two marbles without replacement

therefore for first draw we have 3 white marble to choose among 8 marbles

i.e.

$_{1}^{3}\textrm{C}$  choices among the total of $_{1}^{8}\textrm{C}$ options

For second draw we 2 white marbles left therefore no of ways in which a white marble can be choosen is

$_{1}^{2}\textrm{C}$

Therefore required probability is =$\frac{favourable\ outcome}{Total\ outcome}$

P$\left ( required\right )$=$\frac{3\times2}{8\times7}$

P$\left ( required\right )$=$\frac{3}{28}$