Answer: First option is correct.
Step-by-step explanation:
Since we have given that
probability that an individual is left handed = 0.11
Probability that an individual is not left handed = 1-0.11 = 0.89
so, we need to find the probability of finding five left handers.
We will use "Binomial distribution":
P(X=5)=[tex]^{29}C_5(0.11)^5(0.89)^{24}=0.11[/tex]
Hence, the probability of finding five left handers is 0.11.
Therefore, First option is correct.