Answer:
e= 0.440 mV(millivolt)
Explanation:
Given Magnetic field B= 0.50T
[tex]A_{1}=3\times10^{-3}[/tex]
[tex]A_{2}=1.6\times10^{-3}\\[/tex]
Δt= 1.6sec
[tex] induced emf e=\frac{\mathrm{d} \phi }{\mathrm{d} t}[/tex]
⇒[tex]e=B\frac{\mathrm{d} A}{\mathrm{d} t}[/tex]
[tex]e=0.50\times\frac{3\times10^{-3}-1.6\times10^{-3}}{1.6}[/tex]
[tex]e=0.440\times10^{-3} volt[/tex]
e= 0.440 mV(millivolt)