A wire along the z axis carries a current of 6.8 A in the z direction Find the magnitude and direction of the force exerted on a 6.1 cm long length of the wire by a uniform magnetic field with magnitude 0.36 T in the x direction

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Answer:

Force is 14.93N along positive y axis.

Explanation:

We know that force 'F' on a current carrying conductor placed in a magnetic field of intensity B is given by

[tex]\overrightarrow{F}=\overrightarrow{Il}\times \overrightarrow{B}[/tex]

where L is the length of the conductor

Applying values in the equation we have force F =

[tex]\overrightarrow{F}=6.8\times 6.1\widehat{k}\times 0.36\widehat{i}\\\\\overrightarrow{F}=41.48\widehat{k}\times 0.36\widehat{i}\\\\\therefore \overrightarrow{F}=14.93N\widehat{j}[/tex]

Thus force is 14.93N along positive y axis.

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