Answer:
Force is 14.93N along positive y axis.
Explanation:
We know that force 'F' on a current carrying conductor placed in a magnetic field of intensity B is given by
[tex]\overrightarrow{F}=\overrightarrow{Il}\times \overrightarrow{B}[/tex]
where L is the length of the conductor
Applying values in the equation we have force F =
[tex]\overrightarrow{F}=6.8\times 6.1\widehat{k}\times 0.36\widehat{i}\\\\\overrightarrow{F}=41.48\widehat{k}\times 0.36\widehat{i}\\\\\therefore \overrightarrow{F}=14.93N\widehat{j}[/tex]
Thus force is 14.93N along positive y axis.