Question

The force between two electrical charges is 0.3 N. What would be the force if the charges are doubled, and the distance between them increased by 100%?

(Please show clear steps/explanation)

Answer 1

Answer:

The new force F' will be same of the original force F.

Explanation:

Given that,

Charges = 0.3

We need to calculate the force between the charges

Suppose that the distance between the charges is r.

The force between the charges

$F =\dfrac{kq_{1}q_{2}}{r^2}$

Put the value into the formula

$F=\dfrac{k\times0.3\times0.3}{r^2}$

$F=\dfrac{k\times(0.09)}{r^2}$

If the charges are doubled, and the distance between them increased by 100%.

So, The charges are 0.6 and the distance is 2r.

Then,

The force between the charges

$F'=\dfrac{k\times0.6\times0.6}{(2r)^2}$

$F'=\dfrac{k\times0.09}{r^2}$

$F'=F$

Hence, The new force F' will be same of the original force F.