Question

A nontemplate strand of bacterial DNA has the base sequence 5′−ATGATACTAAGGCCC−3′ Determine the amino acids that will be encoded by this sequence. Add the amino acids from left to right in the order the amino acids will be translated.

Answer 1

Answer:

5′−ATGATACTAAGGCCC−3′

3'--TACTATGATTCCGGG--5'

5'-AUGAUACUAAGGCCC-3'

Ile-Ile-Leu-Arg-Pro

Explanation:

To decode which amino acids will be encoded by the sequence, first the strand must be translated. Remember G pairs with C and T (replaced with an U)  with A.

With the translated strand once, use the amino acids decoder chart, and separate the strand in codons. For each codon  follow the left column for the first letter, the top column for the second, and the right column for the third.

Answer 2

Answer:

fMet-Ile- Leu-Arg-Pro.

Explanation:

First of all, the DNA sequence will need to be transcribed into its respective mRNA so as to know the codons that will that will translate to each amino acid.

However, for a non-template DNA strand, the DNA sequence is the same as the mRNA sequence except that the thymine base in DNA is replaced with uracil base in the mRNA.

Hence,  5′−ATGATACTAAGGCCC−3′ will become 5'-AUGAUACUAAGGCCC-3'.

The first codon AUG represents the start codon (Methionine) and using the genetic codon table

AUA = isoleusine (Ile)

CUA = leucine (leu)

AGG = Arginine (arg)

CCC = proline (pro)

Adding the amino acids from left to right in order of translation, it becomes fMet-Ile- Leu-Arg-Pro.