Help please! I need answers quickly :((
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Answer:
y = - [tex]\frac{1}{2}[/tex] x + 2
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁ ) = (0, 2) and (x₂, y₂ ) = (4, 0) ← 2 points on the line
m = [tex]\frac{0-2}{4-0}[/tex] = [tex]\frac{-2}{4}[/tex] = - [tex]\frac{1}{2}[/tex]
The line crosses the y- axis at (0, 2) ⇒ c = 2
y = - [tex]\frac{1}{2}[/tex] x + 2 ← equation of line
Answer:
x + 2y = 4
Step-by-step explanation:
The y intercept (where it crosses the y axis) is (0,2)
Another point on the line is (4,0)
We can find the slope from these two points
m = (y2-y1)/(x2-x1)
= (0-2)/(4-0)
=-2/4 = -1/2
We have the slope and the y intercept
y = mx+b where m is the slope and b is the y intercept
y = -1/2x +2
We want the equation of the line in standard form
Ax +By =C
Add -1/2x to each side
1/2x +y = -1/2x +1/2x +2
1/2x +y = 2
Multiply by 2 because we do not want fractions
2(1/2x +y) = 2* 2
x + 2y = 4