Question

Solve the following system of algebraic equations: Y = 1-x^2 and y = 1+x

Answer 1

Answer:

x=0;   x=1

Explanation:

The system presents a quadratic equation and a linear equation. Therefore, the result will have two solutions.

The first step is to match the two equations:

$1+x=1-x^{2}$

Then we clear the equation by zeroing.

$0=x^{2} +x+1-1$

Now we perform indicated operations

$x^{2} +x=0$

We factor with the common factor method

x(x+1)=0

We equal each factor to zero and get the results

x=0

(x+1)=0

x=-1

The two values ​​that satisfy both equations are 0 and -1