Given:
L = 1 mH = [tex]1\times 10^{-3}[/tex] H
total Resistance, R = 11 [tex]\Omega[/tex]
current at t = 0 s,
[tex]I_{o}[/tex] = 2.8 A
Formula used:
[tex]I = I_{o}\times e^-{\frac{R}{L}t}[/tex]
Solution:
Using the given formula:
current after t = 0.5 ms = [tex]0.5\times 10^{-3} s[/tex]
for the inductive circuit:
[tex]I = 2.8\times e^-{\frac{11}{1\times 10^{-3}}\times 0.5\times 10^{-3}}[/tex]
[tex]I = 2.8\times e^-5.5[/tex]
I =0.011 A
