Question

What is an equation of the line that is perpendicular to y - 4 = 2(x-6) and
passes through the point (-3,-5)?
O A y+5-}(x+3)
O B. y-5=-2(x-3)
O C.-5--3)
D.y+ 5 = 2(x + 3)​

Answer 1

Answer:

y+5 = -1/2(x+3)

Step-by-step explanation:

y - 4 = 2(x-6)

This is in point slope form (y-y1) = m(x-x1)  

so the slope is 2

We want a line perpendicular so we take the negative reciprocal

m perpendicular is -(1/2)

The new slope is -1/2

We have a slope and a point, so we can use point slope form

(y-y1) = m(x-x1)  

y--5 = -1/2(x--3)

y+5 = -1/2(x+3)