Question

2 Points
An athlete jumps with a speed of 4 m/s at an angle of 23º. How long does the
athlete stay in the air?
O A. 0.32 s
O B. 0.925
O C. 0.55 s
O D. 0.75 s

Answer 1

Answer:

A. 0.32s

Explanation:

Lets find the initial velocity of the vertical component

Cos23=u/4

4cos23=1.6m/s

then time, t =2u/g

2×1.6/9.8

=0.32seconds

Answer 2

Answer:

A. 0.32 s

Explanation:

The other answer did the math wrong but came up with the same answer. Anyway, you're supposed to use sin.

4sin(23) gives you 1.56 or 1.6

-1.56/-9.8 (negative because gravity is working against the direction of of the athlete as he goes into the air) = 0.159...

0.159*2 = 0.318

Round: 0.32