Transverse waves with a speed of 50.0 m/s are to be produced on a stretched string. A 5.00-m length of string with a total mass of 0.060 0 kg is used. (a) What is the required tension in the string? (b) Calculate the wave speed in the string if the tension is 8.00 N.

Respuesta :

Answer:

part a)

T = 30 N

part b)

v = 25.8 m/s

Explanation:

Part a)

As we know that the wave speed in the string is given as

[tex]v = \sqrt{\frac{T}{\mu}[/tex]

here we know that

[tex]\mu = \frac{m}{L}[/tex]

[tex]\mu = \frac{0.060}{5} = 0.012 kg/m[/tex]

now we will have

[tex]50 = \sqrt{\frac{T}{0.012}}[/tex]

now for tension force we have

[tex]T = 30 N[/tex]

Part b)

if the tension in the string is reduced to

T = 8.00 N

so now we will have

[tex]v = \sqrt{\frac{T}{\mu}}[/tex]

[tex]v = \sqrt{\frac{8}{0.012}}[/tex]

[tex]v = 25.8 m/s[/tex]