Answer:
part a)
T = 30 N
part b)
v = 25.8 m/s
Explanation:
Part a)
As we know that the wave speed in the string is given as
[tex]v = \sqrt{\frac{T}{\mu}[/tex]
here we know that
[tex]\mu = \frac{m}{L}[/tex]
[tex]\mu = \frac{0.060}{5} = 0.012 kg/m[/tex]
now we will have
[tex]50 = \sqrt{\frac{T}{0.012}}[/tex]
now for tension force we have
[tex]T = 30 N[/tex]
Part b)
if the tension in the string is reduced to
T = 8.00 N
so now we will have
[tex]v = \sqrt{\frac{T}{\mu}}[/tex]
[tex]v = \sqrt{\frac{8}{0.012}}[/tex]
[tex]v = 25.8 m/s[/tex]