Respuesta :
Answer:So we can say that the rate of reaction increases by factor of 6.
Explanation:
The rate law for any given reaction
A+B⇄C+D
Rate law for the above reaction is:
R=K[A]ᵃ[B]ᵇ
a and b are the order of reaction and it is an experimentally determined quantity.
K is the rate constant and it is constant for a given reaction
[A] and [B] are the concentrations of the reactants.
R is the rate of reaction
For the given reaction :
H₂O₂(aq.)+I₂(aq.)⇆OH⁻(aq.)+HIO(aq.)
Also it is given for the reaction that order with respect to H₂O₂ is 1 and order with respect to I₂ is also 1
The rate law can be written as :
R=K[H₂O₂]¹[I₂]¹
k=rate constant
When we increase the concentration of H₂O₂ by half which meansthat new concentration of H₂O₂ will be= 3/2[H₂O₂].
When we increase the concentration of I₂ by 4 which means that new concentration of I₂ will be= 4[I₂]
Putting the values of our new concentration in the rate law:
R=K3/2[H₂O₂]¹4[I₂]¹
R=6K[H₂O₂]¹[I₂]¹=New rate
So as we can see that the new rate of the reaction using the new concentration is 6 times the older rate of reaction.
So we can say that the rate of reaction increases by factor of 6.
