Question

In getting ready to slam-dunk the ball, a basketball player starts from rest and sprints to a speed of 5.4 m/s in 2.6 s. assuming that the player accelerates uniformly. Determine the distance he runs.

Answer 1

Answer:

Distance, x = 6.99 meters

Explanation:

It is given that,

Initially, the object is at rest, u = 0

Final speed of the basketball player, v = 5.4 m/s

Time taken, t = 2.6 s

Let x is the distance covered by the player. We need to find x. The acceleration of the player is :

$a=\dfrac{v-u}{t}$

$a=\dfrac{5.4\ m/s}{2.6\ s}=2.07\ m/s^2$

Now, calculating the distance covered by the player using second equation of motion as :

$x=ut+\dfrac{1}{2}at^2$

$x=0+\dfrac{1}{2}\times 2.07\ m/s^2\times (2.6\ s)^2$

x = 6.99 meters

So, the distance covered by the basketball player is 6.99 meters.