7^2 x 7^8/ 7^4 = 7^a/ 7^4 =7^b
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Answer:
The value of a is 10 and the value of b is 6
Step-by-step explanation:
* Lets revise how to solve the problem
- Remember in the number with exponent
- a^n × a^m = a^(n + m)
- a^n ÷ a^m = a^(n - m)
Lets solve the problem
∵ [tex]\frac{7^{2}.7x^{8}}{7x^{4}}[/tex]
- Lets use the rule above
∵ [tex]7^{2}.7^{8}=7^{2+8}=7^{10}[/tex]
∴ [tex]\frac{7^{2}.7^{8}}{x^{4}}=\frac{7^{10}}{7^{4}}[/tex]
∵ [tex]\frac{7^{10}}{7^{4}}=\frac{7^{a}}{7^{4}}[/tex]
∴ a = 10
∵ [tex]\frac{7^{10}}{7^{4}}=7^{10-4}=7^{6}[/tex]
∵ [tex]7^{6}=7^{b}[/tex]
∴ b = 6
* The value of a is 10 and the value of b is 6