Question

If a 2500 kg truck is placed on a garage lift platform with an area of 3 m ^ 2, what area would the input piston have to have to lift the truck with 25 lb of force

Answer 1

Answer:

A_1 = 0.0135 m2

Explanation:

GIVEN DATA:

mass of SECOND truck m2 =2500 kg

mass of FIRST truck  m1 = 25 lb = 11.33kg

Area A2 = 3 m2

according to the pascal's law,  pressure at one point is equal to pressure exerted on the other side, therefore we have

$P_{1 }= P_{2}$

we know that

$pressure = \frac{force}{area}$

$\frac{f_{1}}{A_{1}} =\frac{f_{2}}{A_{2}}$

$A_{2} =\frac{f_{2}}{F_{1}}* A_{1}$

$A_{2} = \frac{m_{2}}{m_{1}}*A_{1}$

$3 = \frac{2500}{11.33}*A_{1}$

A_1 = 0.0135 m2