Answer:
a)$1628.90
b)$1647.00
c)$1648.72
Step-by-step explanation:
The question is on compound interest.
The formula to apply here is;
[tex]A=P(1+\frac{r}{n} )^{nt}[/tex]
where
a) If compounded annually, n=1
p=$1000, r=5%=0.05 t=10
Amount will be;
[tex]A=1000(1+\frac{0.05}{1} )^{10} \\\\\\A=1000(1.05)^{10} \\\\\\A=1000*1.6289=1628.90[/tex]
Amount=$1628.90
b) If compounded monthly, n=12
p=$1000, r=5%=0.05, t=10, n=12
[tex]A=1000(1+\frac{0.05}{12} )^{12*10} \\\\\\A=1000(1.0042)^{120} \\\\\\A=1000*1.647=1647[/tex]
Amount=$1647.00
c)If interest compounded continuously, it means the principal is earning interest constantly and the interest keeps earning on the interest earned.Here the formula to apply is;
A=Pe^rt where e is the mathematical constant e=2.71828182846
Hence the amount will be;
[tex]A=Pe^{rt} \\\\\\A=1000*e^{0.05*10} \\\\\\A=1000*2.71828182846^{0.5} \\\\\\A=1648.72[/tex]
Amount=$1648.72