Please Hurry!!
Consider the two-way table below.
Find P(BIC).
![Please Hurry Consider the twoway table below Find PBIC class=](https://us-static.z-dn.net/files/d56/26357c575a7fd628baf32de039d84245.png)
Answer: the answer is B, or P(B|C)=9/24=0.38
Step-by-step explanation:
If you look at the table, you can see that 9 is where BC is. So, 9 is the numerator. The denominator is 24 because that is the total number.
Also, I got this answer correct on Edge
Answer: [tex]P(B|C)=\dfrac{9}{24}=0.38[/tex]
Step-by-step explanation:
The formula for conditional probability :-
[tex]P(M|N)=\dfrac{P(M\cap N)}{P(N)}[/tex]
From the given table it can be seen that ,
Total = 70
[tex]n(C)=24[/tex]
Then , the probability of having B:-
[tex]\text{P(C)}=\dfrac{\text{n(C)}}{\text{Total}}\\\\=\dfrac{24}{70}[/tex]
Also, [tex]n(B\cap C)=9[/tex]
Then , the probability of having the intersection of B and C :-
[tex]P(B\cap C)=\dfrac{n(B\cap C)}{\text{Total}}\\\\=\dfrac{9}{70}[/tex]
Then , by the formula of conditional probability , we have :-
[tex]P(B|C)=\dfrac{P(B\cap C)}{P(C)}\\\\=\dfrac{\dfrac{9}{70}}{\dfrac{24}{70}}\\\\=\dfrac{9}{24}=\dfrac{3}{8}=0.375\approx0.38[/tex]