Question

Starting from the front door of a ranch house, you walk 60.0 m due east to a windmill, turn around, and then slowly walk 40.0 m west to a bench, where you sit and watch the sunrise. It takes you 28.0 s to walk from the house to the windmill and then 36.0 s to walk from the windmill to the bench. For the entire trip from the front door to the bench, what are your (a) average velocity and (b) average speed?

Answer 1

Answer:

Part a)

$velocity = 0.3125 m/s$

Part b)

$speed = 1.5625 m/s$

Explanation:

Part a)

As we know that average velocity is defined as the ratio of displacement and time interval

so here we have

$v = \frac{displacement}{time}$

so here she start from her house and move towards east at 60 m distance  then she turn back and moves towards west by 40 m distance

Now we know that time taken by it to move 60 meter distance is 28 s and then time taken to move next 40 m distance is 36 s

so here displacement is given as

$displacement = 60 - 40 = 20 m$

now total time taken be it is given as

$T = 28 s + 36 s$

$T = 64 s$

now average velocity is given as

$v_{avg} = \frac{20}{64} = 0.3125 m/s$

Part b)

now we know that total distance of whole motion is given as

$d = d_1 + d_2$

$d = 60 + 40 = 100 m$

total time = 64 s

now average speed is given as

$speed = \frac{100}{64} = 1.5625 m/s$

Answer 2

The average velocity will be equal to 0.3125 m/s while the average speed will be equal to 1.5625 m/s.

What is the average velocity?

We know that the average velocity is defined as the ratio of displacement to total time taken to reach that position. therefore,

$Velocity = \dfrac{Displacement}{time}$

Given to us

The displacement between the front door of a ranch house and the bench is 20m,

Time taken to cover that distance = 36 + 28 = 64 sec

$Velocity = \dfrac{20}{64} = 0.3125\rm\ m/s$

What is the average speed?

Average speed is defined as the ratio of total distance covered to total time taken for the entire journey.

$\rm Average\ Speed= \dfrac{Total\ Distance}{time}$

Given to us

Total distance = 60 + 40 = 100 m

Total time = 36s +28s = 64 sec

$\rm Average\ Speed= \dfrac{100}{64} = 1.5625\ m/s$

Hence, the average speed of the man is 1.5625 m/s.

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