Answer:
minimum horizontal force required to start the block motion is F = 0.41 mg
Explanation:
As we know that box is placed on the horizontal floor
so here the normal force on the box is counter balanced by the weight of the box
so we will have
[tex]F_n = mg[/tex]
now in order to displace the box from its position we need to apply the external force which will just exceed the limiting static friction force
So here we will have
[tex]F_s = \mu_s F_n[/tex]
here we know that
[tex]\mu_s = 0.41[/tex]
[tex]F_s = 0.41(mg)[/tex]
so minimum horizontal force required to start the block motion is F = 0.41 mg