Answer:
c) The magnitude of the magnification of a concave mirror is less than 1
Explanation:
we know
the mirror formula is given as:
[tex]\frac{1}{v}+\frac{1}{u}=\frac{2}{r}[/tex] ..............(1)
also
magnification (m) of mirror is given as:
[tex]m=\frac{-v}{u}[/tex] . ..... (2)
where,
v = image distance
u = object distance
r = Radius of curvature of the mirror
Now
from (2)
[tex]v=-mu[/tex]
substituting in (1), we get
[tex]\frac{1}{u}(\frac{1}{-m}+1)=\frac{2}{r}[/tex]
or
[tex]\frac{1}{2}(1-\frac{1}{m})=\frac{u}{r}[/tex] ..............(3)
now it is given that object is beyond the center of the the curvature
thus,
⇒[tex]\frac{u}{r}>1[/tex] ................(4)
comparing the (3) and (4), we have
[tex]\frac{1}{2}(1-\frac{1}{m})>1[/tex]
or
[tex](1-\frac{1}{m})>2[/tex]
or
[tex]-\frac{1}{m}>2-1[/tex]
or
[tex]-\frac{1}{m}>1[/tex]
⇒[tex]m<-1[/tex]
Hence, the magnification is less than 1