Check the picture below.
well, the purple trapezoid, has a height of 5, and its bases are of 5 units and 8 units, recall the bases are the parallel sides in a trapezoid.
now, the yellow rectangle, is a 6x5, and it has those two green triangles in it, well, if we simply get the area of the rectangle, 30 anyway, and subtract the areas of those green triangles, what's leftover, is the rest of the shape on points DEFA.
keeping in mind that the green triangles have a base of 4 and a height of 3 for the one atop and base of 5 and height of 2 for the bottom one.
[tex]\bf \stackrel{\textit{purple trapezoid}}{\cfrac{\stackrel{h}{5}(\stackrel{a}{5}+\stackrel{b}{8})}{2}}~~+~~\left[ \stackrel{\textit{yellow square}}{(6\cdot 5)}-\stackrel{\textit{two green triangles}}{\cfrac{1}{2}(4)(3)-\cfrac{1}{2}(5)(2)} \right] \\\\\\ \cfrac{5(13)}{2}+[30-6-5]\implies \cfrac{65}{2}+[19]\implies \cfrac{103}{2}\implies 51\frac{1}{2}[/tex]
