Why is the answer to this C and not E. Don’t you usually keep the negative number negative? Why is this one not left negative?
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Answer:
C
Step-by-step explanation:
Given
x² = 7x - 3 ( subtract 7x - 3 from both sides )
x² - 7x + 3 = 0 ← in standard form
with a = 1, b = - 7, c = 3
Using the quadratic formula to solve for x
x = ( - (- 7) ± [tex]\sqrt{(-7)^2-(4(1)(3)}[/tex] ) / 2
= ( 7 ± [tex]\sqrt{49-12}[/tex] ) / 2
= [tex]\frac{7+/-\sqrt{37} }{2}[/tex] → C