Answer:
The distance of ship B from the Harbor is 32.26 miles
Step-by-step explanation:
Hello, great question. These types are questions are the beginning steps for learning more advanced Equations.
I have added a visual aid of the problem. As we can see the courses of both ship to the harbor forms a triangle with ship B being the hypotenuse. Since we are given the distance of the course for ship A and the angle between both ships, we can use this information with the COSINE operator to solve for the length of the course of ship B.
[tex]cos(x) = \frac{adjacent}{hypotenuse}[/tex]
[tex]cos(47) = \frac{22miles}{hypotenuse}[/tex] .... flip both fractions.
[tex]\frac{1}{cos(47)} = \frac{hypotenuse}{22miles}[/tex] .... multiply both sides by 22
[tex]\frac{22mi}{cos(47)} = hypotenuse[/tex]
[tex]32.26mi = hypotenuse = B[/tex]
So the distance of ship B from the Harbor is 32.26 miles
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