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Answer:

phonomath. it saves lives in math

Answer:

with the process for the first one you could do the others.

[tex]x=5[/tex] and [tex]y=2[/tex]

Step-by-step explanation:

We have two linear equations

[tex]4x+3y=26[/tex] and [tex]\frac{y}{3}=\frac{x}{3}-1[/tex]

From the second equation we can find y then

[tex]y=3(\frac{x}{3}-1)[/tex]

[tex]y=3\frac{x}{3}-3[/tex]

[tex]y=x-3[/tex]

Now we use this expression of y in the first equation

[tex]4x+3y=26[/tex]

[tex]4x+3(x-3)=26[/tex]

[tex]4x+3x-9=26[/tex]

[tex]7x=26+9[/tex]

[tex]x=\frac{35}{7}[/tex]

[tex]x=5[/tex]

Now que can find the value of y

[tex]y=x-3[/tex]

[tex]y=5-3[/tex]

[tex]y=2[/tex]

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