Question

In the standard x,y coordinate plane, what is the midpoint of the line segment that has endpoint 3,8 and 1,-4

Answer 1

Answer:

the answer would be 2

Step-by-step explanation:

The question is what is the value of 8x-3 over x and the answer to that question is 2 and hears why (8x multiplying by 1/2)-3 over 1\2 = 4 - 3 over 1/2 and half of 8 is 4 so 1 over 1/2 = 1 x 2 over 1 x 1 = 2

Answer 2

The midpoint of the line segment is (2,2).

Important information:

• Two endpoints of a line segment are (3,8) and $(1,-4)$.

We need to find the midpoint of the line segment.

Midpoint:

Two endpoints of a line segment are (3,8) and $(1,-4)$. So, the midpoint is:

$\text{Midpoint}=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$

$\text{Midpoint}=\left(\dfrac{3+1}{2},\dfrac{8+(-4)}{2}\right)$

$\text{Midpoint}=\left(\dfrac{4}{2},\dfrac{4}{2}\right)$

$\text{Midpoint}=\left(2,2\right)$

Thus, the midpoint of the line segment is (2,2).

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