Answer:
Step-by-step explanation:
Since we are talking about compounded annual interest, we can use the Exponential Growth Formula to calculate the answer for this question.
[tex]y = a* (1+r)^{t}[/tex]
Where:
First we need to calculate the total after 2 years with a 9% interest.
[tex]y = 1000* (1+0.09)^{2}[/tex]
[tex]y = 1000* (1.09)^{2}[/tex]
[tex]y = 1000* 1.1881[/tex]
[tex]y = 1188.1[/tex]
So after 2 years there will be £1,188.10 in the account. Now we can add £3000 to that and use the new value as the initial amount, and calculate the new total in 5 years.
[tex]y = (1188.1+3000)* (1+0.09)^{5}[/tex]
[tex]y = 4188.1* (1.09)^{5}[/tex]
[tex]y = 4188.1* 1.5386 [/tex]
[tex]y = 6443.91[/tex]
So now we can subtract the £4000 purchase from the amount currently in the account, and calculate one more year of interest with the new initial amount.
[tex]y = (6443.91-4000)* (1+0.09)^{1}[/tex]
[tex]y = (2443.91)* 1.09[/tex]
[tex]y = 2663.86[/tex]
So at the end you would have £2,662.86 in the account one year after the purchase.