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Select the correct answer.

What is the nth term of the geometric sequence 4, 8, 16, 32, ...?

A. `a_(n)=2(4)^(n-1)`

B. `a_(n)=4(2)^(n-1)`

C. `a_(n)=2(n)^4`

D. `a_n=4(n)^2`

Respuesta :

Find the common ratio between each number given:

8/4 = 2

16/8 = 2

32/16 = 2

The common ratio is constant at 2, which means the next number would be 32 x 2.

A geometric series equation is written as an = a1r^n-1

Where a1 is the first term, r is the ratio and n is the term you want to find.

r was determined to be 2. The first term is given as 4 ( the first number in the series).

This means the equation becomes an = 4(2)^n-1

The answer would be B.

Answer:

The answer is B

Step-by-step explanation:

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