Question

Write the first four terms of the sequence.

ak = 2 + 3k, for all integers k ≥ 1

Answer 1

Answer:

The first four terms of the sequence are:

$a_{1} = 5$

$a_{2} = 8$

$a_{3} = 11$

$a_{4} = 14$

Step-by-step explanation:

To find a term in the sequence, we have to replace the sequence for a concrete value of k.

Since the sequence is defined for all integers k ≥ 1, then the first value is k = 1. Then, the first  four terms are 1, 2, 3 and 4.

Let's evaluate the sequence with these values...

$a_{1} = 2 + 3(1) = 2 + 3 = 5 => a_{1} = 5$

$a_{2} = 2 + 3(2) = 2 + 6 = 8 => a_{2} = 8$

$a_{3} = 2 + 3(3) = 2 + 9 = 11 => a_{3} = 11$

$a_{4} = 2 + 3(4) = 2 + 12 = 14 => a_{4} = 14$