Answer:
[tex]14878.04878miles/hours^2[/tex]
Step-by-step explanation:
Let's find a solution by understanding the following:
The acceleration rate is defined as the change of velocity within a time interval, which can be written as:
[tex]A=(Vf-Vi)/T[/tex] where:
A=acceleration rate
Vf=final velocity
Vi=initial velocity
T=time required for passing from Vi to Vf.
Using the problem's data we have:
Vf=65miles/hour
Vi=6miles/hour
T=14.8seconds
Using the acceleration rate equation we have:
[tex]A=(65miles/hour - 6miles/hour)/14.8seconds[/tex], but look that velocities use 'hours' unit while 'T' uses 'seconds'.
So we need to transform 14.8seconds into Xhours, as follows:
[tex]X=(14.8seconds)*(1hours/60minutes)*(1minute/60seconds)[/tex]
[tex]X=0.0041hours[/tex]
Using X=0.0041hours in the previous equation instead of 14.8seconds we have:
[tex]A=(65miles/hour - 6miles/hour)/0.0041hours[/tex]
[tex]A=(61miles/hour)/0.0041hours[/tex]
[tex]A=(61miles)/(hour*0.0041hours)[/tex]
[tex]A=61miles/0.0041hours^2[/tex]
[tex]A=14878.04878miles/hours^2[/tex]
In conclusion, the acceleration rate is [tex]14878.04878miles/hours^2[/tex]