Answer:
m<AED = 92°
Step-by-step explanation:
It is given that,
measure of arc BC = 38° therefore m<BDC = 38/2 = 19°
measure of arc AD = 146° therefore m<ACD = 146/2 = 73°
To find the measure of <CED
Consider the ΔCDE
m<D = m<BDC = 19° and
m<C = m<ACD = 73°
By using angle sum property m<CED can be written as,
m<CED = 180 -( m<D + m<C )
= 180 - (19 + 73)
= 180 - 92
= 88°
To find the measure of <AED
<AED and <CED are linear pair
m<AED + m<CED = 180
m<AED = 180 - m<CED
= 180 - 88
= 92°
Therefore m<AED = 92°
