Question

True-breeding flies with red eyes and long wings were crossed to flies with white eyes and miniature wings. All F1 offspring had red eyes and long wings. The F1 females flies were then crossed to males with white eyes and miniature wings. The following results were obtained for the F2 generation:
204 red eyes, long wings
208 white eyes, miniature wings
40 red eyes, miniature wings
48 white eyes, long wings
What is the map distance between these two genes?

Answer 1

Answer:

176m.u.

Explanation:

Map distance can be calculated by the following formula:

Map distance = $\frac{\text{Recombinant off spring}}{\text{total number of offspring}}\times 1000$

Recombinant offsprings are redeyes, miniature wings + white eyes, long wings.

Recombinant offspring = 40 + 48

=88.

Total number of offspring = 204 + 208 + 40 + 48

= 500

Map distance = $\frac{88}{500}\times1000$

Map distance = 176 m.u.

The map distance between two genes is 176 m.u.