Answer: The required force = 4.7 x 105 N
Explanation:
Mass of the ship m = 1.00 x 107 Kg
Initial speed u = 0.750 m/s
Final speed v = 0 m/s
Average speed s =( 0.750 + 0) / 2 = 0.375 m/s
Time taken to bring the ship to rest t = [tex]\frac{distance}{speed}[/tex]
= [tex]\frac{6}{0.375}[/tex]
= 16 s
Average force exerted on the pier F =[tex]\frac{m(v - u )}{t}[/tex]
F = [tex]\frac{1.00 x 107 ( 0 - 0.750 )}{16}[/tex]
F = - 4.7 x 105 N
Hence the required force = 4.7 x 105 N