Question

The following data summarizes results from 941 pedestrian deaths that were caused by accidents. If one of the pedestrian deaths is randomly selected, find the probability that the pedestrian was intoxicated or the driver was intoxicated.
Pedestrian Pedestrian
Intoxicated Not intoxicated
Driver Intoxicated 56 71
Driver Not intoxicated 292 522

Answer 1

Answer:

P=0.3698  or 36.98%

Step-by-step explanation:

Complete the table by adding the totals to each column and row.

                                Pedestrian     Pedestrian

                                Intoxicated    Not intoxicated Totals

Driver Intoxicated           56                     71               127

Driver Not intoxicated   292                   522             814

Totals                            348                    593             941

The probability that the pedestrian was intoxicated or the driver was intoxicated is the opposite event of neither of them was intoxicated.  The total of cases when neither of them was intoxicated is 593. So the probability is:

P1=593/941=0.6302

The probability of the opposite event is one minus the probability calculated:

P=1-0.6302=0.3698

And this is the probability that the pedestrian was intoxicated or the driver was intoxicated.