Question

Find the product. (3p^4)^3 · (p^2)^7

Answer 1

Answer: $27p^{26}$

Step-by-step explanation:

In this case, you need to use the Power of a power property, which states that:

$(a^m)^n=a^{mn}$

And the Product of powers property, which states that:

$(a^m)(a^n)=a^{(m+n)}$

Then, applying this, we get the following product:

$(3p^4)^3*(p^2)^7=27p^{(4)(3)}*p^{(2)(7)}=27p^{12}*p^{14}=27p^{(12+14)}=27p^{26}$