Answer:
[tex]P(t)=80(10^{0.1t})[/tex]
Step-by-step explanation:
The 'y' axis represent log(P), so it may be modeled as a line (or linear function), where its slope is 0.1:
[tex]log(P)=0.1t+C[/tex]
Pow each part of the equation by 10:
[tex]10^{log(P)}=10^{0.1t+C}\\ P=10^{0.1t+C}[/tex]
Evaluate at t=0, where the population is known.
[tex]P(0)=10^{C}=80[/tex]
Applying logarithmic properties:
[tex]P=10^{0.1t+C}=10^{0.1t}*10^{C}[/tex]
So, the final function is:
[tex]P(t)=80(10^{0.1t})[/tex]