Respuesta :

Answer:

c for the question that says what point is on [tex]y=\log_a(x)[/tex] given the options.

9  for the question that reads: "If [tex]\log_a(9)=4[/tex], what is the value of [tex]a^4[/tex].

Step-by-step explanation:

We are given [tex]y=\log_a(x)[/tex].

There are some domain restrictions:

[tex]a \text {is number between } 0 \text{ and } 1 \text{ or greater than } 1[/tex]

[tex]x \ge 0[/tex]

a) couldn't be it because x=0 in the ordered pair.

b) isn't is either for the same reason.

c) \log_a(1)=0 \text{ because } a^0=1[/tex]

So c is so far it! Since (x,y)=(1,0) gives us [tex]0=\log_a(1)[/tex] where the equivalent exponential form is as I mentioned it two lines ago.

d) Let's plug in the point and see: (x,y)=(a,0) implies [tex]0=\log_a(a)[/tex].

The equivalent exponetial form is [tex]a^0=a[/tex] which is not true because [tex]a^0=1 (\neq a)[/tex].

If [tex]\log_a(9)=4[/tex]. then it's equivalent exponential form is: [tex]a^4=9[/tex].

Guess what it asked for the value of [tex]a^4[/tex] and we already found that by writing your equation [tex]\log_a(9)=4[/tex] in exponential form.

Note:

The equivalent exponential form of [tex]\log_a(x)=y[/tex] implies [tex]a^y=x[/tex].

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