Question

Select the correct answer.
If a line crosses the y-axis at (0, 1) and has a slope of 4/5, what is the equation of the line?

Answer 1

Answer:

5y - 4x = 5. This gives you your points with a slope of 4/5

Answer 2

Answer:

$y=\frac{4}{5}x+1$

Step-by-step explanation:

We are given the slope, and the y-intercept. So we can use the slope-intercept equation. Which is as follows:

$y=mx+b$

where $m$ is the slope and $b$ is the y-intercept (the value of $y$ when $x=0$).

The information that we have is that the slope of the line is:

$m=\frac{4}{5}$

and that the line crosses the y-axis at (0, 1).

From this point we can find the y-intercept $b$, because b is the value of $y$ when $x=0$.

And since the line passes through (0, 1) when $x = 0$, $y =1$. Thus, the y-intercept is:

$b=1$

substituting the values of the slope and the y-intercept into the equation:

$y=mx+b\\y=\frac{4}{5}x+1$

the answer is:   $y=\frac{4}{5}x+1$