Question

The vertex form of the equation of a parabola is y=(x-3)^2+35 what is the standard form of the equation

Answer 1

Answer:

x^2 -6x+44

Step-by-step explanation:

Develop form of (x-3)^2 is x^2 - 6x +9

Then y= x^2 -6x +9 + 35

So, y= X^2 -6x +44

Answer 2

Answer:

$y=x^2 -6x+44$

Step-by-step explanation:

The standard form of a quadratic equation is:

$y = ax ^ 2 + bx + c$.

In this case we have the following quadratic equation in vertex form

$y=(x-3)^2+35$

Now we must rewrite the equation in the standard form.

$y=(x-3)(x-3)+35$

Apply the distributive property

$y=x^2 -3x -3x +9+35$

$y=x^2 -6x+9+35$

$y=x^2 -6x+44$

the standard form of the equation is: $y=x^2 -6x+44$