Question

Find the limit of the function algebraically. x→−3 (x^2-9/x^3+3)
a) -6
b) -3
c) does not exist
d) 0

Answer 1

Answer:

  d)  0

Step-by-step explanation:

The function is defined for x=-3, so it can simply be evaluated there.

$\displaystyle\lim_{x \to -3}\left(\frac{x^2-9}{x^3+3}\right)=\frac{(-3)^2-9}{(-3)^3+3}=\frac{9-9}{-27+3}=0$