Enter the equation of the circle described below.
Center (-1,4), radius = sqrt3
![Enter the equation of the circle described below Center 14 radius sqrt3 class=](https://us-static.z-dn.net/files/df1/1cefda2bffe2c1f58703c9bb1c0e8340.png)
Answer:
(x + 1)² + (y - 4)² = 3
Step-by-step explanation:
The equation of a line in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
here (h, k) = (- 1, 4) and r = [tex]\sqrt{3}[/tex], hence
(x - (- 1))² + (y - 4)² = ([tex]\sqrt{3}[/tex] )², that is
(x + 1)² + (y - 4)² = 3 ← equation of circle