Question

solve using the quadratic formula x2+3x-3=0

Answer 1

Answer:

x=(-3+-sqrt15)/2

Step-by-step explanation:

Without using calculatorsoup,

we can use the quadratic formula for x^2+3x-3=0

using it we find:

x=(-b+-sqrtb^2-4ac)/2a

x=(-3+-sqrt3-4*1*-3)/2

x=(-3+-sqrt15)/2

Answer 2

For this case we must resolve the following expression:

$x ^ 2 + 3x-3 = 0$

The roots will be given by:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2 (a)}$

We have to:

$a = 1\\\b = 3\\c = -3$

So:

$x = \frac {-3 \pm \sqrt {3 ^ 2-4 (1) (- 3)}} {2 (1)}\\x = \frac {-3 \pm \sqrt {9 + 12}} {2}\\x = \frac {-3 \pm \sqrt {21}} {2}$

We have two roots:

$x_ {1} = \frac {-3+ \sqrt {21}} {2} = 0.7913\\x_ {2} = \frac {-3- \sqrt {21}} {2} = - 3.7913$

Answer:

$x_ {1} = \frac {-3+ \sqrt {21}} {2} = 0.7913\\x_ {2} = \frac {-3- \sqrt {21}} {2} = - 3.7913$