Question

Based on Pythagorean identities, which equation is true?
O sin?e 1-cos?
O sec?etan? --1
O -cos?-1--sin
O cote-csc? --1

Answer 1

Answer:

d no is correct

I hope it will help you

Answer 2

The equivalent Pythagorean identity is $-cos^2 \theta - 1 = -sin^2 \theta$

Pythagoras theorem

According to the theorem;

$x^2 + y^2 = r^2$

Given the following

x = $r cos \theta$

y = $r sin \theta$

Substitute into the formula

$(rcos \theta)^2 + (r sin \theta)^2 = r^2\\cos^2 \theta + sin^2 \theta =1$

Multiplying through by minus, the equivalent Pythagorean identity is $-cos^2 \theta - 1 = -sin^2 \theta$

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