Answer:
B
Step-by-step explanation:
We are given:
[tex]y=4x[/tex]
[tex]2x^2-y=0[/tex]
We are going to put 4x in place of the second y since the first y equaled it:
[tex]2x^2-4x=0[/tex]
So we can factored this equation:
[tex]2x(x-2)=0[/tex]
This implies 2x=0 or x-2=0.
2x=0
Divide both sides by 2:
x=0
x-2=0
Add 2 on both sides:
x=2
If x=0 and y=4x, then y=4(0)=0 so we have (0,0) is an intersection.
If x=2 and y=4x, then y=4(2)=8 so we have (2,8) is an intersection.
