Respuesta :
f(x)=(x-5)(x-4)(x-2)
x-5=0
x-5+5=0+5
x=5
x-4=0
x-4+4=0+4
x=4
x-2=0
x-2+2=0+2
x=2
Answer: 5,4,2 -C
The zeros of the function f(x) = (x-5)(x-4)(x-2) are 5, 4, 2
Option C is correct
Note that:
The zeros of a function f(x) are the values of x that makes f(x) to be equal to zero
If f(x) = (x - a)(x - b)(x - c), then the zeros of the function f(x) are:
x = a, x = b, x = c
Therefore, the zeros of f(x)=(x-5)(x-4)(x-2) are found by equating f(x) to zero
(x - 5)(x - 4)(x - 2) = 0
Equate each of the terms to zero
x - 5 = 0
x = 5
x - 4 = 0
x = 4
x - 2 = 0
x = 2
The zeros of the function f(x) = (x-5)(x-4)(x-2) are 5, 4, 2
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