Respuesta :

f(x)=(x-5)(x-4)(x-2)

x-5=0

x-5+5=0+5

x=5

x-4=0

x-4+4=0+4

x=4

x-2=0

x-2+2=0+2

x=2

Answer: 5,4,2 -C

The zeros of the function f(x) = (x-5)(x-4)(x-2) are 5, 4, 2

Option C is correct

Note that:

The zeros of a function f(x) are the values of x that makes f(x) to be equal to zero

If f(x)  =  (x - a)(x - b)(x - c), then the zeros of the function f(x) are:

x  = a,  x  =  b,  x  =  c

Therefore, the zeros of f(x)=(x-5)(x-4)(x-2) are found by equating f(x) to zero

(x - 5)(x - 4)(x - 2)  =  0

Equate each of the terms to zero

x  -  5  =  0

x  =   5

x  -  4  =  0

x   =  4

x  -  2  =  0

x   =  2

The zeros of the function f(x) = (x-5)(x-4)(x-2) are 5, 4, 2

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