Question

Find an equation for the line that passes through the points (-2, 1) and (6, -5)

Answer 1

Answer:

y=-3/4x-1/2

Step-by-step explanation:

Using the slope equation,

m=y₂-y₁

    ____

     x₂-x₁

you get the slope:

m=-5-1/6+2

m=-6/8

m=-3/4

We find that the intercept is -1/2.

The equation is y=-3/4x-1/2

Answer 2

Hello!

The answer is:

The equation of the line that passes through the points (-2,1) and (6,-5) is:

$y=-\frac{3}{4}x-\frac{1}{2}$

Why?

To solve the problem, we can use the following formula:

We have that:

$y-y_1=\frac{y_2-y_1}{x_2-x_1}*(x-x_1)$

So, using the given points (-2,1) and (6,-5), we have:

$y-1=\frac{-5-1}{6-(-2)}*(x-(-2))$

$y-1=\frac{-6}{6+2}*(x+2)$

$y-1=\frac{-6}{8}*(x+2)$

$y-1=-\frac{3}{4}*(x+2)$

$y=-\frac{3}{4}*(x+2)+1$

$y=-\frac{3}{4}*(x)-\frac{3}{4}**(2)+1$

$y=-\frac{3}{4}(x)-\frac{6}{4})+1$

$y=-\frac{3}{4}(x)-\frac{3}{2})+1$

$y=-\frac{3}{4}x-\frac{1}{2}$

Hence, we have that the equation of the line that passes through the points (-2,1) and (6,-5) is:

$y=-\frac{3}{4}x-\frac{1}{2}$

Have a nice day!