Respuesta :
Answer to Problem: [tex]6x+\frac{1}{4}(4x+8)>12[/tex]
[tex]x>\frac{10}{7}[/tex]
So this says any number larger than 10/7 is a solution.
A graph to represent the solution:
O~~~~~~~~~~~~~~~~~~~~ x>10/7
---------------------------(10/7)---------------------
Step-by-step explanation:
We are given:
[tex]6x+\frac{1}{4}(4x+8)>12[/tex]
I'm going to distribute first:
[tex]6x+x+2>12[/tex]
Combine like terms:
[tex]7x+2>12[/tex]
Subtract 2 on both sides:
[tex]7x>10[/tex]
Divide both sides by 7:
[tex]x>\frac{10}{7}[/tex]
So this says any number larger than 10/7 is a solution.
A graph to represent the solution:
O~~~~~~~~~~~~~~~~~~~~ x>10/7
---------------------------(10/7)---------------------
I used an open circle because there wasn't a line under the inequality (no line under to represent equals).
Answer:
x>10/7
Step-by-step explanation:
distribute first:
6x+x+2>12
Combine like terms:
7x+2>12
Subtract 2 on both sides:
7x>10
Divide both sides by 7:
x>10/7