Respuesta :

Answer to Problem: [tex]6x+\frac{1}{4}(4x+8)>12[/tex]

[tex]x>\frac{10}{7}[/tex]

So this says any number larger than 10/7 is a solution.

A graph to represent the solution:

                                O~~~~~~~~~~~~~~~~~~~~ x>10/7

---------------------------(10/7)---------------------

Step-by-step explanation:

We are given:

[tex]6x+\frac{1}{4}(4x+8)>12[/tex]

I'm going to distribute first:

[tex]6x+x+2>12[/tex]

Combine like terms:

[tex]7x+2>12[/tex]

Subtract 2 on both sides:

[tex]7x>10[/tex]

Divide both sides by 7:

[tex]x>\frac{10}{7}[/tex]

So this says any number larger than 10/7 is a solution.

A graph to represent the solution:

                                O~~~~~~~~~~~~~~~~~~~~ x>10/7

---------------------------(10/7)---------------------

I used an open circle because there wasn't a line under the inequality (no line under to represent equals).

Answer:

x>10/7

Step-by-step explanation:

distribute first:

6x+x+2>12

Combine like terms:

7x+2>12

Subtract 2 on both sides:

7x>10

Divide both sides by 7:

x>10/7

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