Question

A: what is the discriminators for the quadratic equation?

B:based on the discriminant which statement about the number and type of solutions in the equation is correct?

Answer 1

$\bf \qquad \qquad \qquad \textit{discriminant of a quadratic} \\\\\\ \stackrel{\stackrel{a}{\downarrow }}{1}x^2\stackrel{\stackrel{b}{\downarrow }}{+6}x\stackrel{\stackrel{c}{\downarrow }}{+9}=0 ~~~~~~~~ \stackrel{discriminant}{b^2-4ac}= \begin{cases} 0&\textit{\underline{one solution}}~~\textit{\Large \checkmark}\\ positive&\textit{two solutions}\\ negative&\textit{no solution} \end{cases} \\\\\\ 6^2-4(1)(9)\implies 36-36\implies 0$

Answer 2

Answer:

0

Step-by-step explanation:

Descriminator is calculated by the following formula:

b*b - 4 * a * c, where a,b,c are the numbers in equitation.