Question

What is the distance between the polnts (3, 2) and (15, 16) on a coordinate plane?

Answer 1

Answer:

C. 15 units

Step-by-step explanation:

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We have the points (3, 7) and (15, 16). Substitute:

$d=\sqrt{(15-3)^2+(16-7)^2}=\sqrt{12^2+9^2}=\sqrt{144+81}=\sqrt{225}=15$