Answer:
Part 5) The roots are x=-3 and x=1.5
Part 6) The solution on a number line is the shading area below of the line y=-1/3 (close circle)
Step-by-step explanation:
Part 5) Find the roots of the parabola given by the following equation
[tex]2x^{2} +5x-9=2x[/tex]
we know that
The formula to solve a quadratic equation of the form [tex]ax^{2} +bx+c=0[/tex] is equal to
[tex]x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}[/tex]
in this problem we have
[tex]2x^{2}+5x-2x-9=0[/tex]
[tex]2x^{2}+3x-9=0[/tex]
so
[tex]a=2\\b=3\\c=-9[/tex]
substitute in the formula
[tex]x=\frac{-3(+/-)\sqrt{3^{2}-4(2)(-9)}} {2(2)}[/tex]
[tex]x=\frac{-3(+/-)\sqrt{81}} {4}[/tex]
[tex]x=\frac{-3(+/-)9} {4}[/tex]
[tex]x=\frac{-3(+)9} {4}=1.5[/tex]
[tex]x=\frac{-3(-)9} {4}=-3[/tex]
therefore
The roots are x=-3 and x=1.5
Part 6) Solve the inequality and graph the solution on a number line.
[tex]-3(5y-4)\geq 17[/tex]
Solve for y
[tex]-15y+12\geq 17[/tex]
Subtract 12 both sides
[tex]-15y\geq 17-12[/tex]
[tex]-15y\geq 5[/tex]
Multiply by -1 both sides
[tex]15y\leq -5[/tex]
Divide by 15 both sides
[tex]y\leq -1/3[/tex]
The solution is the interval -----> (-∞, -1/3]
All real numbers less than or equal to negative one third
The solution on a number line is the shading area below of the line y=-1/3 (close circle)
The graph in the attached figure