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5.Find the roots of the parabola given by the following equation.
2x2+ 5x - 9 = 2x

6.Solve the inequality and graph the solution on a number line.
–3(5y – 4) ≥ 17

Respuesta :

Answer:

Part 5) The roots are x=-3 and x=1.5

Part 6) The solution on a number line is the shading area below of the line y=-1/3 (close circle)

Step-by-step explanation:

Part 5) Find the roots of the parabola given by the following equation

[tex]2x^{2} +5x-9=2x[/tex]

we know that

The formula to solve a quadratic equation of the form [tex]ax^{2} +bx+c=0[/tex] is equal to

[tex]x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}[/tex]

in this problem we have

[tex]2x^{2}+5x-2x-9=0[/tex]

[tex]2x^{2}+3x-9=0[/tex]

so

[tex]a=2\\b=3\\c=-9[/tex]

substitute in the formula

[tex]x=\frac{-3(+/-)\sqrt{3^{2}-4(2)(-9)}} {2(2)}[/tex]

[tex]x=\frac{-3(+/-)\sqrt{81}} {4}[/tex]

[tex]x=\frac{-3(+/-)9} {4}[/tex]

[tex]x=\frac{-3(+)9} {4}=1.5[/tex]

[tex]x=\frac{-3(-)9} {4}=-3[/tex]

therefore

The roots are x=-3 and x=1.5

Part 6) Solve the inequality and graph the solution on a number line.

[tex]-3(5y-4)\geq 17[/tex]

Solve for y

[tex]-15y+12\geq 17[/tex]

Subtract 12 both sides

[tex]-15y\geq 17-12[/tex]

[tex]-15y\geq 5[/tex]

Multiply by -1 both sides

[tex]15y\leq -5[/tex]

Divide by 15 both sides

[tex]y\leq -1/3[/tex]

The solution is the interval -----> (-∞, -1/3]

All  real numbers less than or equal to negative one third

The solution on a number line is the shading area below of the line y=-1/3 (close circle)

The graph in the attached figure

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